Optimal. Leaf size=336 \[ -\frac{a^2 b C d^3-a^3 d^3 D+a b^2 d \left (-3 B d^2-6 c^2 D+4 c C d\right )+b^3 \left (-\left (-5 A d^3+2 B c d^2-2 c^3 D\right )\right )}{b^2 d^2 \sqrt{c+d x} (b c-a d)^3}+\frac{-3 a^2 b C d^3+3 a^3 d^3 D+3 a b^2 B d^3+b^3 \left (-\left (5 A d^3-2 B c d^2+2 c^2 C d-2 c^3 D\right )\right )}{3 b^3 d^2 (c+d x)^{3/2} (b c-a d)^2}-\frac{A-\frac{a \left (a^2 D-a b C+b^2 B\right )}{b^3}}{(a+b x) (c+d x)^{3/2} (b c-a d)}-\frac{\tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d x}}{\sqrt{b c-a d}}\right ) \left (-a^2 b (C d-6 c D)+a^3 (-d) D-a b^2 (4 c C-3 B d)+b^3 (2 B c-5 A d)\right )}{b^{3/2} (b c-a d)^{7/2}} \]
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Rubi [A] time = 0.791175, antiderivative size = 336, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 32, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125, Rules used = {1621, 897, 1261, 208} \[ -\frac{a^2 b C d^3-a^3 d^3 D+a b^2 d \left (-3 B d^2-6 c^2 D+4 c C d\right )+b^3 \left (-\left (-5 A d^3+2 B c d^2-2 c^3 D\right )\right )}{b^2 d^2 \sqrt{c+d x} (b c-a d)^3}+\frac{-3 a^2 b C d^3+3 a^3 d^3 D+3 a b^2 B d^3+b^3 \left (-\left (5 A d^3-2 B c d^2+2 c^2 C d-2 c^3 D\right )\right )}{3 b^3 d^2 (c+d x)^{3/2} (b c-a d)^2}-\frac{A-\frac{a \left (a^2 D-a b C+b^2 B\right )}{b^3}}{(a+b x) (c+d x)^{3/2} (b c-a d)}-\frac{\tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d x}}{\sqrt{b c-a d}}\right ) \left (-a^2 b (C d-6 c D)+a^3 (-d) D-a b^2 (4 c C-3 B d)+b^3 (2 B c-5 A d)\right )}{b^{3/2} (b c-a d)^{7/2}} \]
Antiderivative was successfully verified.
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Rule 1621
Rule 897
Rule 1261
Rule 208
Rubi steps
\begin{align*} \int \frac{A+B x+C x^2+D x^3}{(a+b x)^2 (c+d x)^{5/2}} \, dx &=-\frac{A-\frac{a \left (b^2 B-a b C+a^2 D\right )}{b^3}}{(b c-a d) (a+b x) (c+d x)^{3/2}}+\frac{\int \frac{-\frac{b^3 (2 B c-5 A d)-a b^2 (2 c C-3 B d)+3 a^3 d D-a^2 b (3 C d-2 c D)}{2 b^3}-\frac{(b c-a d) (b C-a D) x}{b^2}-\left (c-\frac{a d}{b}\right ) D x^2}{(a+b x) (c+d x)^{5/2}} \, dx}{-b c+a d}\\ &=-\frac{A-\frac{a \left (b^2 B-a b C+a^2 D\right )}{b^3}}{(b c-a d) (a+b x) (c+d x)^{3/2}}-\frac{2 \operatorname{Subst}\left (\int \frac{\frac{-c^2 \left (c-\frac{a d}{b}\right ) D+\frac{c d (b c-a d) (b C-a D)}{b^2}-\frac{d^2 \left (b^3 (2 B c-5 A d)-a b^2 (2 c C-3 B d)+3 a^3 d D-a^2 b (3 C d-2 c D)\right )}{2 b^3}}{d^2}-\frac{\left (-2 c \left (c-\frac{a d}{b}\right ) D+\frac{d (b c-a d) (b C-a D)}{b^2}\right ) x^2}{d^2}-\frac{\left (c-\frac{a d}{b}\right ) D x^4}{d^2}}{x^4 \left (\frac{-b c+a d}{d}+\frac{b x^2}{d}\right )} \, dx,x,\sqrt{c+d x}\right )}{d (b c-a d)}\\ &=-\frac{A-\frac{a \left (b^2 B-a b C+a^2 D\right )}{b^3}}{(b c-a d) (a+b x) (c+d x)^{3/2}}-\frac{2 \operatorname{Subst}\left (\int \left (\frac{3 a b^2 B d^3-3 a^2 b C d^3+3 a^3 d^3 D-b^3 \left (2 c^2 C d-2 B c d^2+5 A d^3-2 c^3 D\right )}{2 b^3 d (b c-a d) x^4}+\frac{-a^2 b C d^3+a^3 d^3 D-a b^2 d \left (4 c C d-3 B d^2-6 c^2 D\right )+b^3 \left (2 B c d^2-5 A d^3-2 c^3 D\right )}{2 b^2 d (b c-a d)^2 x^2}+\frac{d \left (b^3 (2 B c-5 A d)-a b^2 (4 c C-3 B d)-a^3 d D-a^2 b (C d-6 c D)\right )}{2 b (b c-a d)^2 \left (b c-a d-b x^2\right )}\right ) \, dx,x,\sqrt{c+d x}\right )}{d (b c-a d)}\\ &=\frac{3 a b^2 B d^3-3 a^2 b C d^3+3 a^3 d^3 D-b^3 \left (2 c^2 C d-2 B c d^2+5 A d^3-2 c^3 D\right )}{3 b^3 d^2 (b c-a d)^2 (c+d x)^{3/2}}-\frac{A-\frac{a \left (b^2 B-a b C+a^2 D\right )}{b^3}}{(b c-a d) (a+b x) (c+d x)^{3/2}}-\frac{a^2 b C d^3-a^3 d^3 D+a b^2 d \left (4 c C d-3 B d^2-6 c^2 D\right )-b^3 \left (2 B c d^2-5 A d^3-2 c^3 D\right )}{b^2 d^2 (b c-a d)^3 \sqrt{c+d x}}-\frac{\left (b^3 (2 B c-5 A d)-a b^2 (4 c C-3 B d)-a^3 d D-a^2 b (C d-6 c D)\right ) \operatorname{Subst}\left (\int \frac{1}{b c-a d-b x^2} \, dx,x,\sqrt{c+d x}\right )}{b (b c-a d)^3}\\ &=\frac{3 a b^2 B d^3-3 a^2 b C d^3+3 a^3 d^3 D-b^3 \left (2 c^2 C d-2 B c d^2+5 A d^3-2 c^3 D\right )}{3 b^3 d^2 (b c-a d)^2 (c+d x)^{3/2}}-\frac{A-\frac{a \left (b^2 B-a b C+a^2 D\right )}{b^3}}{(b c-a d) (a+b x) (c+d x)^{3/2}}-\frac{a^2 b C d^3-a^3 d^3 D+a b^2 d \left (4 c C d-3 B d^2-6 c^2 D\right )-b^3 \left (2 B c d^2-5 A d^3-2 c^3 D\right )}{b^2 d^2 (b c-a d)^3 \sqrt{c+d x}}-\frac{\left (b^3 (2 B c-5 A d)-a b^2 (4 c C-3 B d)-a^3 d D-a^2 b (C d-6 c D)\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d x}}{\sqrt{b c-a d}}\right )}{b^{3/2} (b c-a d)^{7/2}}\\ \end{align*}
Mathematica [A] time = 1.07435, size = 334, normalized size = 0.99 \[ \frac{\sqrt{c+d x} \left (a \left (a^2 D-a b C+b^2 B\right )-A b^3\right )}{b (a+b x) (b c-a d)^3}-\frac{2 \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d x}}{\sqrt{b c-a d}}\right ) \left (3 a^2 b c D+a^3 (-d) D+a b^2 (B d-2 c C)+b^3 (B c-2 A d)\right )}{b^{3/2} (b c-a d)^{7/2}}+\frac{d \left (A b^3-a \left (a^2 D-a b C+b^2 B\right )\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d x}}{\sqrt{b c-a d}}\right )}{b^{3/2} (b c-a d)^{7/2}}+\frac{2 \left (-A d^3+B c d^2-c^2 C d+c^3 D\right )}{3 d^2 (c+d x)^{3/2} (b c-a d)^2}+\frac{b \left (4 A d^3-2 B c d^2+2 c^3 D\right )-2 a d \left (B d^2+3 c^2 D-2 c C d\right )}{d^2 \sqrt{c+d x} (a d-b c)^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.025, size = 730, normalized size = 2.2 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.66378, size = 593, normalized size = 1.76 \begin{align*} \frac{{\left (6 \, D a^{2} b c - 4 \, C a b^{2} c + 2 \, B b^{3} c - D a^{3} d - C a^{2} b d + 3 \, B a b^{2} d - 5 \, A b^{3} d\right )} \arctan \left (\frac{\sqrt{d x + c} b}{\sqrt{-b^{2} c + a b d}}\right )}{{\left (b^{4} c^{3} - 3 \, a b^{3} c^{2} d + 3 \, a^{2} b^{2} c d^{2} - a^{3} b d^{3}\right )} \sqrt{-b^{2} c + a b d}} + \frac{\sqrt{d x + c} D a^{3} d - \sqrt{d x + c} C a^{2} b d + \sqrt{d x + c} B a b^{2} d - \sqrt{d x + c} A b^{3} d}{{\left (b^{4} c^{3} - 3 \, a b^{3} c^{2} d + 3 \, a^{2} b^{2} c d^{2} - a^{3} b d^{3}\right )}{\left ({\left (d x + c\right )} b - b c + a d\right )}} - \frac{2 \,{\left (3 \,{\left (d x + c\right )} D b c^{3} - D b c^{4} - 9 \,{\left (d x + c\right )} D a c^{2} d + D a c^{3} d + C b c^{3} d + 6 \,{\left (d x + c\right )} C a c d^{2} - 3 \,{\left (d x + c\right )} B b c d^{2} - C a c^{2} d^{2} - B b c^{2} d^{2} - 3 \,{\left (d x + c\right )} B a d^{3} + 6 \,{\left (d x + c\right )} A b d^{3} + B a c d^{3} + A b c d^{3} - A a d^{4}\right )}}{3 \,{\left (b^{3} c^{3} d^{2} - 3 \, a b^{2} c^{2} d^{3} + 3 \, a^{2} b c d^{4} - a^{3} d^{5}\right )}{\left (d x + c\right )}^{\frac{3}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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